Hmmm... It looks like taking the intersection of (Z/2Z)^n and K then using it to quotient K should have been sufficient, but in the end the method I wanted to use does not work ^^;
Modeling my problem as I was doing leads to false answers, and I do not think it can be fixed... Well, thank you anyway, It was still a good occasion to work with Sage's matrices ! :-) Nathann On Jul 17, 12:17 am, Nathann Cohen <nathann.co...@gmail.com> wrote: > Hello everybody !!!! > > I have a small Linear Algebra question for you... I am pretty sure it > has a well-known answer, but this is where I feel how far my linear > algebra is... :-) > > Actually, it is a simple one. I have one matrix M defined over Z^n, > whose kernel K is of interest to me. I would then like to find the > intersection of K with (Z/2Z)^n, and a basis of it. > > I am pretty sure I have been taught the answer somehow, or should at > least know where to look for it.... ^^; > > Thank youuuuuuu !!! > > Nathann -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
