thank you chris, I thought about something like that but I could not "catch" this 'NO DATA etc'.
On 19 juil, 17:51, chris wuthrich <[email protected]> wrote: > > > A related question: is it possible to catch an exception if there is a > > > time out? > > I think there should be. The timeout process should raise an exception > which can be catch. Right now, one can catch that it sends back a > string 'NO DATA (timed out)' rather than a result. So the following > should do. But that is not the way it should be IMHO. > > @fork(timeout=1) > def mon_factor(n): > return factor(n) > > for m in [randint(10,100) for i in [1..10]]: > N = 10^m +127 > ff = mon_factor(N) > if type(ff) != type('a'): > print "success : %s"%ff > else: > print "no success : %s"%ff > > Chris. -- To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
