Dear all, I'm sorry I have yet again something to bother you with. Running the following few lines:
eq=5-e^x print "1:",eq.substitute(x=3*x) print "2:",eq.substitute(x=log(x)) yields the output (Sage 4.5.2 with Ubuntu): 1: -e^(3*x) + 5 2: -log(x) + 5 So 1 is fine, but it seems that to get to 2 Sage actually substitutes twice no: 5-e^x -> 5-x -> 5-log(x). I had expected it would just give me 5-x rather, is it a bug or a feature? Thanks again, Kees -- To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
