On Dec 2, 7:38 am, Santanu Sarkar <[email protected]>
wrote:
> Let A be a matrix of order (24,6). How one can find a matrix B in Sage of
> order (6,24) such that
> AB=Identity matrix?

There is no such matrix, since AB cannot have rank more than 6.

Did you mean to solve BA = 6x6 identity?  That would have a solution
iff A has rank 6.

John Cremona

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