Thank you!  This is now reported to Maxima at
http://sourceforge.net/tracker/?func=detail&aid=3167163&group_id=4933&atid=104933

On Jan 28, 10:38 am, Loïc <xl...@free.fr> wrote:
> With maxima 5.23.2:
>
> (%i1) radcan((2*x^2/(x^2+1)-1)/sqrt(-4*x^2/(x^2+1)^2+1) );
> (%o1)
> 1
> radcan(((2*x^2-x^2-1)/(x^2+1))/sqrt((x^2-1)^2/(x^2+1)^2));
>
> 2
>
> x  - 1
> (%o2)
> --------
>                                                                               
>           !
> 2    !
>                                                                               
>           !
> x  - 1!
> radcan(((x^2-1)*x/(x^2+1)^2-x/(x^2+1))/sqrt(-(x^2-1)^2/(x^2 +
> 1)^2 + 1) );
>
> x
> (%o3)
> - ---------------
>
> 2
>
> (x  + 1) abs(x)
>
> same results
>
> Thus, where reporting this bug?
>
> On 27 jan, 22:41, kcrisman <kcris...@gmail.com> wrote:
>
>
>
> > Hmm.
>
> > Maxima 5.22.1http://maxima.sourceforge.net
> > using Lisp ECL 10.4.1
> > Distributed under the GNU Public License. See the file COPYING.
> > Dedicated to the memory of William Schelter.
> > The function bug_report() provides bug reporting information.
> > (%i1) radcan((2*x^2/(x^2+1)-1)/sqrt(-4*x^2/(x^2+1)^2+1) );
> > (%o1)                                  1
> > (%i2) radcan(((2*x^2-x^2-1)/(x^2+1))/sqrt((x^2-1)^2/(x^2+1)^2));
> >                                      2
> >                                     x  - 1
> > (%o2)                              --------
> >                                    ! 2    !
> >                                    !x  - 1!
> > (%i3) radcan(((x^2-1)*x/(x^2+1)^2-x/(x^2+1))/sqrt(-(x^2-1)^2/(x^2 +
> > 1)^2 + 1) );
> >                                         x
> > (%o3)                          - ---------------
> >                                    2
> >                                  (x  + 1) abs(x)
>
> > I don't have access to a current Maxima, but if someone could check
> > this out in 5.23.2 or whatever the latest is, that would be really
> > great.  Then we'd have to file a bug report there.  Certainly the
> > behavior should be similar for these.
>
> > - kcrisman

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