On Feb 8, 10:30 am, tvn <[email protected]> wrote: > this is what I am trying to do -- is there a way to have it to return uk = > w-y ? [...] > sage: solve([uk + x + 2*y == A*B, w + x + y == A*B],[uk,x]) > [[uk == w - y, x == A*B - w - y]]
You answer your own question. > sage: solve([uk + x + 2*y == A*B, w + x + y == A*B],[uk,y]) > [[uk == -A*B + 2*w + x, y == A*B - w - x]] It is a useful exercise to reason why returning "uk == w - y" as part of the answer here should be considered an error. Hint: look up the "dict" option on solve. -- To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
