On May 12, 11:19 pm, kcrisman <[email protected]> wrote:
> This should, in theory, give a plot of li(20^z) along the critical
> line of the Riemann zeta function.  Unfortunately, as you will see if
> you plot this, it succeeds until it hits a branch cut (I assume), and
> does not look so nice, not to mention missing the actual interesting
> behavior.

You probably want ei(log(20)*z), not li(20^z).

Fredrik

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