On Aug 1, 11:10 pm, "D. S. McNeil" <[email protected]> wrote: > > Thanks for this. There still seems to be a manual step in going from, > > say, > > s1 = 2*(1,8) - (1,9) > > to > > s1 = 2*b[1] - b[2] > > I may be misunderstanding you. Are you saying you want to enter the line > > s1 = 2*(1,8)-(1,9) > > verbatim and have it work?
No, s1 will be the result of a calculation on sums of modular symbols over various residue classes. Sorry if I was not expressing myself clearly enough. Jack -- To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
