Hi, On Thu, Sep 29, 2011 at 2:17 AM, globaljavaprogrammer <[email protected]> wrote: > how can I use sage to compute the inverse of a function like f(x) = (x > +1)^2?
sage: f = (x + 1)^2 sage: g = 1 / f sage: h = f^(-1) sage: f*g 1 sage: g*f 1 sage: f*h 1 sage: h*f 1 -- Regards Minh Van Nguyen -- To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
