On 30/11/11 00:22, Dan Drake wrote:
> x, n = var('x n')
> a(n) = x^n # formula for the nth term
> assume(0<x<1)
> limit(a(n+1)/a(n), n=infinity)Thanks very much, it works perfectly! I did not think of searching for a limit function, however, I should have. Thanks a lot! I. -- Q: Because it reverses the logical flow of conversation. A: Why is putting a reply at the top of the message frowned upon? -- To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
