On Tue, Mar 13, 2012 at 10:27 AM, Kakaz <[email protected]> wrote:
> Thanks for answer.
>
> Yes, I did. I found similar question but it was about rsolve and
> second order relation.
> I am looking for rsolve or similar solver in context of several
> variables ( ei. a(n), b(n) in example above and 4 variables in my case
> I want to solve).
>

In this case, I would just plug in c1e^(r1n)+c2e^(r2n) (c1, c2
vectors, r1, r2 complex
numbers/eigenvalues) and use Sage to try to solve.

> I have read this:
> http://groups.google.com/group/sage-support/browse_thread/thread/a58be337b75af4b6/22d16a9f0fef5d72?lnk=gst&q=recurrence#22d16a9f0fef5d72
> and this:
> http://groups.google.com/group/sage-support/browse_thread/thread/6f194a6c01fdb97d/8ecbfcb7361ba5e9?lnk=gst&q=recurrence#8ecbfcb7361ba5e9
>

I was thinking of this:
http://docs.sympy.org/dev/modules/solvers/solvers.html


>
> On Mar 13, 2:59 pm, David Joyner <[email protected]> wrote:
>> I think it is in sympy (included in Sage).
>>
>> I vaguely remember the question has been asked before on
>> this list but I don't remember the exact answer. Did you look through the
>> sage-support archive?
>>
>>
>>
>>
>>
>>
>>
>> On Tue, Mar 13, 2012 at 9:35 AM, Kakaz <[email protected]> wrote:
>> > Of course it should be:
>> > a(n+1) = A*a(n) + B*b(n)
>> > b(n+1) = C*a(n) + D*b(n)
>>
>> > On Mar 13, 2:32 pm, Kakaz <[email protected]> wrote:
>> >> Hi all!
>> >> I would like to ask - is there possibility in Sage ( or Maxima) to
>> >> solve first order recurrence relation given by linear system with
>> >> several variables?
>> >> For example:
>>
>> >> a(n+1) = A*a(n) + B*b(n)
>> >> b(n) = C*a(n) + D*b(n)
>>
>> >> Have I find solution of linear system at first an then solve
>> >> "separated" relation or is there a possibility to solve such system
>> >> directly? As far as I know - rsolve  from sympy -  takes only one
>> >> relation as argument.
>>
>> >> Actually I have such system with 4-variables and rational - constant
>> >> -  coefficients ...
>> >> Thanks!
>> >> Kazek Kurz
>>
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