You could also construct a system for a given plaintext ciphertext pair and 
then substitute the key in every equation. The resulting system should be 
trivial to solve and be != 1.

On Wednesday 02 May 2012, Zoresvit wrote:
> I'm implementing a MQ polynomial system for GOST 28147-89 cipher. The idea
> is similar to polynomial system construction in mq.SR for AES and *ctc.py*
> for Courtois Toy Cipher by Martin Albrecht. And I'm wondering what is the
> best way to test correctness of the system.
> 
> What I've implemented so far:
> 
>    1. replacing every variable by intermediate encryption bits to test the
>    correctness of each equation (system should result 0);
>    2. extracting first round of the system, injecting plaintext and key
>    values and solving this one-round system. The resulting variables should
> be equal to the ciphertext after the first round.
> 
> Are these two tests enough for making sure the system is correct or are
> there any better solutions to this?
> 
> Thanks!

Cheers,
Martin

--
name: Martin Albrecht
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_otr: 47F43D1A 5D68C36F 468BAEBA 640E8856 D7951CCF
_www: http://martinralbrecht.wordpress.com/
_jab: [email protected]

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