[s.id() for s in SymmetricGroup(3).conjugacy_classes_subgroups() if
s.is_transitive()]
--> [[3, 1], [6, 1]]
[s.id() for s in SymmetricGroup(3).subgroups() if s.is_transitive()]
--> [[1, 1], [2, 1], [3, 1], [6, 1]]
This is of course because return types of .subgroups() differs from return
type of .conjugacy_classes_subgroups(). But should it be this way?
--
Jori Mäntysalo
--
You received this message because you are subscribed to the Google Groups
"sage-support" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/sage-support?hl=en.
For more options, visit https://groups.google.com/groups/opt_out.
