Hum... G is bipartite but its complement H is not...
On Monday, April 1, 2013 2:26:12 AM UTC-7, Jason Grout wrote: > > On 3/31/13 9:29 PM, pong wrote: > > G = graphs.CompleteBipartiteGraph(3,3); H=G.complement(); H.show() > > The problem here is that the CompleteBipartiteGraph has a specific > layout that makes the edges of the complement overlap. When you do > H.show, specify a layout that will separate those edges: > > H.show(layout='circular') > > Thanks, > > Jason > > > -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sage-support?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
