John, I agree.  In fact in my case I know a multiple of the order of the 
ideal.  The ideal is one of norm 2, and I can produce an element of norm 
2^k, which is not divisible by 2.  But, I can't find the method to test 
principality, or to extract the generator.  I would like something like

I.principal_generator()

which would either return None if the ideal wasn't principal (or maybe 
throw an exception), otherwise it would return a generator.  I'm sure that 
there's some Pari function to do this, but I don't know what it is.

Victor

On Wednesday, April 3, 2013 4:32:16 AM UTC-4, John Cremona wrote:
>
> If you knew a multiple of the class number, and could factor it,  then 
> you could use that in place of the actual class number. 
>
> Certainly, if your ideal was principal and easy to prove as such then 
> computing the class group would be overkill! 
>
> John 
>
> On 3 April 2013 09:09, Jeroen Demeyer <[email protected] <javascript:>> 
> wrote: 
> > On 2013-04-02 21:13, Victor Miller wrote: 
> >> I have a bunch of ideals in number fields whose orders in the class 
> >> group I want to calculate.  If K is the number field and a is the 
> ideal, 
> >> I had been doing something like 
> >> 
> >> H = K.class_group() 
> >> print H(a).order() 
> >> 
> >> But if K is a big number field this seems wasteful (and takes a long 
> >> time), since it computes the whole class group. 
> > As far as I know, there is no way to do this without computing the class 
> > group. 
> > 
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