Thanks Leif. inspect.getfile() doesn't seem to do what I want.

The situation is that I have a number of scripts, s1.sage, s2.sage, etc,
and I'd like them to be able to write to a '.js' file with the same name as
their filenames, e.g. s3.sage would write to s3.js, etc. I thought I might
be able to do something like open(__name__ + ".js", w")...



On 9 June 2013 15:43, leif <not.rea...@online.de> wrote:

> leif wrote:
>
>> Emil wrote:
>>
>>> I'd like to know if it's possible to get the filename of a script that's
>>> been run using the "load" or "attach" command at the sage: prompt.
>>>
>>> If I insert a "print __name__" in the script I just get "__main__".
>>>
>>> I know __name__ isn't the right thing, since I'm not dealing with an
>>> imported Python module... But it seems like it could be possible that
>>> there is a builtin that gives what I want, but I can't find it...
>>>
>>
>> In Sage, there is attached_files() which gives a list of the filenames.
>>
>>
>> Not sure whether there's some function for just loaded files; doesn't
>> seem Sage would keep track of them.
>>
>
> ... but I probably misread your question.
>
> If the loaded script you want to get the filename of defines some object
> foo, you can use inspect.getfile(foo).
>
> (Probably see also sage/misc/sageinspect.py.)
>
>
>
> -leif
>
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