Thank you. This solution is much quicker, since the list of keys is kept in
order!
On Wednesday, July 3, 2013 8:38:20 PM UTC-5, Volker Braun wrote:
>
> Keep both a set(<keys>) and a dictionary {key:value}. Insert and delete on
> both to keep them in sync.
>
> On Wednesday, July 3, 2013 9:24:42 PM UTC-4, Sam Math wrote:
>>
>> So as you can see, I'm adding 2 elements (in this case, the values are
>> 1... but I have specific values in my program) to the dictionary, but
>> removing the "first" (in the sense of its key). Calling the "min" function
>> seems to be taking time, which is understandable.
>>
>>
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