Dear Vince,
Thank you for your helpful reply.
I'm trying to do something similar to check whether a function is periodic,
I tried:
> bool(sin(x) == sin(x + 2*pi))
which gave 'True' as 2*pi is the period of sine.
However, I wanted to figure out what is the period of the function, so I
tried:
> var('p')
> solve(sin(x) == sin(x + p), p)
I though this would give me 2*pi (and I guess it should also give 4*pi,
6*pi, etc.) but it gave me:
[p == -x + arcsin(sin(x))]
Am I doing something wrong?
Regards, and thanks,
Avril
On Saturday, October 12, 2013 11:08:18 AM UTC+1, Vincent Knight wrote:
>
> Hi Avril,
>
> One approach to check parity for example could be:
>
> sage: f(x) = 1/(1-x^2)
> sage: bool(f(x) == f(-x))
> True
>
> whereas f is not odd as:
>
> sage: bool(f(x) == -f(-x))
> False
>
> There might well be an attribute, method on functions that does this also
> but I'm not aware of it.
> Vince
>
>
> On 12 October 2013 11:03, Avril Coghlan <[email protected] <javascript:>
> > wrote:
>
>> Dear all,
>>
>> I'm wondering whether there is a way to use SAGE to test whether a
>> function such as:
>> f(x) = 1/(1 - x^2)
>> or
>> f(x) = sin(x)
>> is an odd function, even function, or periodic?
>>
>> I'm a Maths student, and am not sure if this is possible, or is a silly
>> question (it seems to me quite a hard thing to check, but I could be
>> totally wrong),
>>
>> Regards,
>> Avril
>> Avril Coghlan
>>
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>
>
> --
> Dr Vincent Knight
> Cardiff School of Mathematics
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