I think that the constructor should return the same type for all
values of i even when the result is a constant.

It is all too easy to implement functions which behave as you show,
when dealing with trivial simple cases: in this case it would be so
easy to write at the start of the function "if i==0: return 1" that I
would not have been surprised if the legendre(0,x) was int(1)!

John

On 11 December 2013 12:40, Thierry Dumont <[email protected]> wrote:
> Hello, all,
>
> I am going to manipulate Legendre (P) polynomials.
> So I do something like this:
>
> sage: P.<x>=QQ[]
>
> sage: #generate de first Lagrange polynomial
> sage: s=[legendre_P(i,x) for i in [0..2]]
> sage: print s
> [1, x, 3/2*x^2 - 1/2]
>
> sage: #now, look at the parents
> sage: s[0].parent()
> Integer Ring
> sage: s[1].parent()
> Univariate Polynomial Ring in x over Rational Field
>
> Ok, this is correct, and seems nice; but I want to evaluate these
> polynomials for  different values of x, and you cannot evaluate a member
> of "Integer Ring" at say, x=1/21... So I need to compute the parent of
> polynomials (which possibly are scalars)  in all my functions, make test
> and so on....
>
> I have found a work-around:
> sage:  s=[P(legendre_P(i,x)) for i in [0..2]]
>
> Then, I get:
>
> sage: s[0].parent()
> Univariate Polynomial Ring in x over Rational Field
>
> Ok, but is there some other way to do this?
>
> Yours
> t.
>
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