I think that Ralf's point is the following

print (4.001^2).n(300)
print ((4001/1000)^2).n(300)

16.0080010000000036995970731368288397789001464843750000000000000000000000000000000000000000
16.0080010000000000000000000000000000000000000000000000000000000000000000000000000000000000


print sqrt(4.001).n(300)
print sqrt(4001/1000).n(300)


2.00024998437695300523841979156713932752609252929687500000000000000000000000000000000000000
2.00024998437695281987761450010498155779765165614814745039069047372837143657067970643422267


which has nothing to do with Pari, but rather that we have the convention 
of "once in a given precision, always there". Note the suspicious powers of 
5 showing up (i.e. negative powers of 2) which presumably have nothing to 
do with the actual answer.  At  http://trac.sagemath.org/ticket/16025 he 
suggests raising a warning - I don't know if that is right, but it would be 
interesting to discuss whether this is user error or a bug or some third 
option.

- kcrisman

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