Thanks Peter.




*Bhavin K Moriya <https://sites.google.com/site/bhavinmoriya/> NASI
Research AssociateHarish Chandra Research Institute
<http://www.hri.res.in/>*
*Chhatnag Road, Jhusi*
*Allahabad - 211 019.*

"Only the gentle are ever really strong."
- James Dean





On Thu, Apr 10, 2014 at 7:12 PM, Peter Bruin <[email protected]> wrote:

> Dear Bhavin,
>
>
> Thank you very much for your answer. It helps but still I do not know how
>> to see the answer to my exact problem.
>> My exact problem is the see the graph of y^2=x(x+1)(2*x+1)/6.
>>
>
> If you have constructed an elliptic curve (after scaling the variables),
> say E, then you can do
>
> sage: E.plot()
>
> Otherwise, you can try something like
>
> sage: R.<x,y>=RR[]
> sage: f=y^2-x*(x+1)*(2*x+1)/6
> sage: C=Curve(f)
> sage: C.plot()
>
> Peter
>
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