OK, but why we need to use "limit" to compute a convergent sum...?
For instance
sum(1/n^2,n,2,oo)
gives pi^2/6-1
but
limit(sum(1/n^2,n,2,x), x=oo)
do not give a result...
Le mercredi 16 avril 2014 12:29:08 UTC+2, [email protected] a écrit :
>
> On Wed, 16 Apr 2014, Alberto Verga wrote:
>
> > n = var('n')
> > sum(log(1-1/n^2),n,2,oo)
> >
> > do not give the answer -log(2), but a 0*infinity error.
>
> limit(sum(log(1-1/n^2),n,2,x), x=oo)
>
> --
> Jori Mäntysalo
>
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