Yes I just started looking at this again about an hour ago. It looks like 
the way Sage gets the map is only by doing linear changes of coordinates on 
P^2 and a Cremona, as outlined here:
http://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&ved=0CCwQFjAA&url=http%3A%2F%2Ftrac.sagemath.org%2Fraw-attachment%2Fticket%2F3416%2Fcubic_to_weierstrass_documentation.pdf&ei=mASBU4zHJ6KlsATngYHQCA&usg=AFQjCNHyMPTkzhy9KhgNr-MB0pI6pJXNTw&sig2=AORDehO_tzL8xrZTO7OLZg&bvm=bv.67720277,d.cWc&cad=rja
In fact I followed the procedure there by hand since I didn't look at the 
actual Sage code and the output was the same exact equation.

On Saturday, May 24, 2014 4:38:48 PM UTC-4, Nils Bruin wrote:
>
> On Saturday, May 24, 2014 9:18:29 AM UTC-7, Volker Braun wrote:
>>
>> Its a 4:1 map so you can't invert it...
>>
>
> I would find that surprising. For a general plane cubic, there are good 
> recipes for getting a 9:1 map to a Weierstrass model in general and a 1:1 
> map when a rational point is specified. A 4:1 map is rather unnatural to 
> get in that situation. You'd expect that from a y^2=quartic in x model.
>
> Indeed, the map returned is invertible, the inverse being:
>
> [   -12*x*z - 4*y*z,  32*x*z,  x^2 - 28*x*z - 4*y*z]
>
>
>

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