A first *very rough* approximation would be
def leaf_count(x):
if x.operator()==None:
return(1)
return(sum(map(leaf_count, x.operands())))
but it's more comicated than that. compare :
sage: leaf_count(sin(a+b))
2
with :
sage: leaf_count(sin(a+b)/tan(a+b))
5
In other words : should function calls be counted or not ?
HTH,
--
Emmanuel Charpentier
Le mercredi 6 août 2014 16:53:30 UTC+2, Nasser M. Abbasi a écrit :
>
> I searched for this but could not find it on google.
>
> Is there a way in sage to determine the size of expression as given
> typically by leaf count? Similar to what is documented in Mathematica
> leafCount[] here
>
> http://reference.wolfram.com/language/ref/LeafCount.html
>
> "gives the total number of indivisible subexpressions in expr."
>
> And also similar to Maple's
>
>
> http://www.maplesoft.com/support/help/Maple/view.aspx?path=MmaTranslator/Mma/LeafCount&term=leafcount
>
> I need a way to measure the size of resulting expression from sage to
> compare it with Mathematica's result and Maple's as well. I currently use
> leafCount() for this since both Maple and Mathematica have this function.
>
> Does sage have similar function or another way to obtain this measure?
>
> For example, given this expression
>
> (c + integrate(e^(2*x + sin(x)), x))*e^(-sin(x))
>
> Then in Mathematica I would write
>
> Clear[x, c];
> expr = (c + Integrate[Exp[2*x + Sin[x]], x])*Exp[-Sin[x]];
> LeafCount[expr]
>
> 19
>
> thanks
> --Nasser
>
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