I have a symmetric real matrix 'A', and I need to factorize it as X(X^T). An n-by-k X where k=rank(A) would be ideal, but a square X with zeros is fine too.
Is there a built-in method I'm not seeing? Or something simpler than looping through the eigenvectors? -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
