Or, if you question is more "sage" than "math" question...
...using sympy from the SAGE-wiki help and website http://byumcl.bitbucket.org/bootcamp2013/labs/sympy.html : example with no "x" symbolic and another one with symbolic "x" import sympy as sym from sympy import Symbol x = sympy.Symbol("x") y = sympy.Symbol("y") roots = sym.solve(y**3 + 2*y**2 + 8, y) print(roots) roots = sym.solve(x^2*y**3 + (5*x+3)*2*y**2 + 8*x, y) print(roots) and filtering the complex (with I) symbolic roots you get the real one. On Friday, 9 January 2015 11:35:01 UTC+1, Santanu wrote: > > Dear all, > > I have one polynomial > f_x(y) =y^3 +f_1(x) y^2 +f_2(x) y + f_3(x). > > Since it is a cubic polynomial, it has atleast > one real root. > I want to find that real root as a function of x. > I know that x \in [a,b]. > > -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-support+unsubscr...@googlegroups.com. To post to this group, send email to sage-support@googlegroups.com. Visit this group at http://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
