Hi

I have no idea how to solve this. If you create and log in as a different
user, does it have the same problem?

(I can confirm my PPA installs do not show this error)

It might also help to ask on an ipython list (but mention that you get this
in sage).
Or install ipython from ppa:jtaylor/ipython and test whether a plot does
the same for you there.

Regards,
Jan

On 14 March 2015 at 17:34, patrick bobbitt <[email protected]>
wrote:

> Yep:
>
> sage: %config DisplayFormatter
> DisplayFormatter options
> ----------------------
> DisplayFormatter.active_types=<List>
>     Current: [u'text/plain']
>     List of currently active mime-types to display. You can use this to
> set a
>     white-list for formats to display.
>     Most users will not need to change this value.
> DisplayFormatter.plain_text_only=<Bool>
>     Current: False
> sage:
>
>
> On Friday, March 13, 2015 at 5:51:34 AM UTC-4, Jan Groenewald wrote:
>>
>> Hi
>>
>> I do not get this error on a PPA install. Do you get this?
>>
>> sage: %config DisplayFormatter
>> DisplayFormatter options
>> ----------------------
>> DisplayFormatter.active_types=<List>
>>     Current: [u'text/plain']
>>     List of currently active mime-types to display. You can use this to
>> set a
>>     white-list for formats to display.
>>     Most users will not need to change this value.
>> DisplayFormatter.plain_text_only=<Bool>
>>     Current: False
>> sage:
>>
>> Regards,
>> Jan
>>
>>
>>
>> On 13 March 2015 at 03:46, patrick bobbitt <[email protected]> wrote:
>>
>>> I've installed the binaries for Ubuntu 14.04 using the PPA:
>>>
>>> apt-add-repository -y ppa:aims/sagemath
>>> apt-get update
>>> apt-get install sagemath-upstream-binary
>>>
>>> When I follow the basic tutorial for making plots I get an error (ANY
>>> help would be appreciated... similar errors barf out with just about any
>>> sort of plot):
>>>
>>> sage: circle((0,0), 1, rgbcolor=(1,1,0))
>>> /usr/lib/sagemath/local/lib/python2.7/site-packages/
>>> IPython/core/formatters.py:239: FormatterWarning: Exception in
>>> text/plain formatter: unexpected unindent (parser.py, line 670)
>>>   FormatterWarning,
>>> ------------------------------------------------------------
>>> ---------------
>>> KeyError                                  Traceback (most recent call
>>> last)
>>> <ipython-input-1-0176f8791dbc> in <module>()
>>> ----> 1 circle((Integer(0),Integer(0)), Integer(1),
>>> rgbcolor=(Integer(1),Integer(1),Integer(0)))
>>>
>>> /usr/lib/sagemath/local/lib/python2.7/site-packages/IPython/core/displayhook.pyc
>>> in __call__(self, result)
>>>     251             self.write_output_prompt()
>>>     252             format_dict, md_dict = self.compute_format_data(
>>> result)
>>> --> 253             self.write_format_data(format_dict, md_dict)
>>>     254             self.update_user_ns(result)
>>>     255             self.log_output(format_dict)
>>>
>>> /usr/lib/sagemath/local/lib/python2.7/site-packages/IPython/core/displayhook.pyc
>>> in write_format_data(self, format_dict, md_dict)
>>>     172         # newline, even if all the prompt separators are ''.
>>> This is the
>>>     173         # standard IPython behavior.
>>> --> 174         result_repr = format_dict['text/plain']
>>>     175         if '\n' in result_repr:
>>>     176             # So that multi-line strings line up with the left
>>> column of
>>>
>>> KeyError: 'text/plain'
>>>
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>>
>>
>>
>> --
>>   .~.
>>   /V\     Jan Groenewald
>>  /( )\    www.aims.ac.za
>>  ^^-^^
>>
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-- 
  .~.
  /V\     Jan Groenewald
 /( )\    www.aims.ac.za
 ^^-^^

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