Hello I am newbie to sagemath. I have windows 8 and sage version is 6.4.1. I am running it inside virtualbox. I was reading some thing about solving equations on sage website at http://www.sagemath.org/doc/reference/calculus/sage/symbolic/relation.html
At one point author is trying to demonstrate the use of optional keywords for the "solve" He is solving equation solve(abs(1-abs(1-x)) == 10, x) When evaluated this gives [abs(abs(x - 1) - 1) == 10] But when the input is modified a little as solve(abs(1-abs(1-x)) == 10, x, to_poly_solve=True) sage gives correct result as [x == -10, x == 12] So why does it not work in the first case ? I didn't understand this use of keyword to_poly_solve. Please help sundar -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
