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Le 03/04/2015 19:19, Jori Mantysalo a écrit :
> On Fri, 3 Apr 2015, Guillaume CONNAN wrote:
> 
>> it's to do something like ( P1 * P2 | a ) & P3 + 2
> 
> Can you give a concrete example of "P1 * P2 | a"?

something like :

p1 = lambda z: ((3*z^3 | 2*z^2) ^^ 5*z) + 2

This is a little bit more tricky algebraicaly speaking than + and *
since some laws are not distributive on others

It is to study code obfuscation (but this is a secret.).

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