On Monday, June 1, 2015 at 7:53:18 PM UTC-5, kcrisman wrote:
>
> I wonder if anyone else has any ideas here?
>
sympy, too, finds the limit despite not recognizing the identity:
%python
​from sympy import *
x = symbols('x')
expr = 27**(log(x,3)/x**3)
expr, limit(expr, x, oo)
>>> (27**(log(x)/(x**3*log(3))), 1)
Steve
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