On Mon, Aug 31, 2015 at 6:58 PM, Jim Huff <[email protected]> wrote:
> The integral of -1/(1-x) should be ln(1-x)
>
> SageMathCloud computes ln(x-1)
>
assume(x>1)
integrate(-1/(1-x),x)
returns ln(x-1), which is correct.
For 0<x<1, if you regard ln() as a multi-valued function on CC-{x<=0}
then ln(x-1) and ln(1-x) differ by a constant.
Hope that helps.
> integrate(-1/(1-x),x)
> RUN
> Result: log(x-1)
>
>
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