+1 for the weird behaviour of symbolic integration...I computed it quicky without comp as integral -f'/f where f(x) = 1+sin x, whose solution seems to be a log f function, and since f equals 0 only f for x = -pi/2 + 2k pi (when sinx = -1), I don't know from which movie is "divergent" coming from.
the integral call is working fine when the lowest bound is replaced by some positive float between 0 and pi/6 Dominique. -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
