z/2 vs 2/z On 05/11/15 00:32, Rob Beezer wrote:
My complex analysis is very rusty, so I can't tell if the problem here is me or Sage:z = var('z') f = e^(z/2) f.residue(z) Result: 0 x = var('x') g = e^x t = g.taylor(x, 0, 5) t(x = 2/z) Result: 2/z + 2/z^2 + 4/3/z^3 + 2/3/z^4 + 4/15/z^5 + 1 So the coefficient of 1/z is 2, and the residue should be 2? Thanks, Rob
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