On 2016-03-31 11:06, Marc Mezzarobba wrote:
Jeroen Demeyer wrote:
Is there any reason that quo_rem is not consistent with .mod()? That
is no longer arbitrary and would also extend the Euclidean division of
univariate polynomials.
Not quite: you'd have to return a tuple of quotients.
I don't get what you mean. What I am saying is that the following two
should return the same answer:
p.mod([q])
p.quo_rem(q)[1]
I see no reason why this is currently not the case.
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