> > How do I get a solution similar to the one for flushes? > > I guess you don't hope for the exact same solution, for exercice "hand of four" than for "flush" :-)
If your question "How do I get" means "How I can code " and is related to the probability to get hand of four (end of exercice),.., why not : Hands = Subsets(Cards, 5) print len(FourOfKinds) / Hands.cardinality() len(FourOfKinds) is 624 because 13 choices for the "kind", 12 choice for the kind of the "odd card" when kind choosen, 4 suits for that card. 624 = 13 x 12 x 4 Dominique -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
