Your question is puzzling since i is a constant, and 1/(s-i) =
(s+i)/(s^2+1) so the expressions are equal.

John Cremona

On 6 Mar 2017 17:35, "Hemanth G" <[email protected]> wrote:

> Dear All,
>
> How do you make SageMath to consider the term "i" as a complex term.Here
> the SageMath is considering "i" as a constant.This question is
> in wake of problem faced in getting Laplace transform of exp(i*x). The
> answer should be [s/(s^2+1)] +i* [1/(s^2+1)] whereas I am getting
> 1/(s-I). The answer should be [s/(s^2+1)] +i* [1/(s^2+1)]  since this
> infers to cos(x)+i*sin(x) when we take the inverse Laplace transform.
> Please refer the codes below.
>
> ##codes used in SageMath
> var('s,x')
> i=sqrt(-1)
> f=exp(i*x)
> f.laplace()
> ## Answer from this code is 1/(s-I)
> ##Required answer is [s/(s^2+1)] +i*[1/(s^2+1)]
>
> Could anyone help me in this matter.Thank you.
>
> With Best Regards/ Mit Besten Grüßen / Sincères Salutations
> Hemanth Gaekwad
>
>
>
>
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