I would like to understand why this definition of the slope of the secant
line does not allow me to define the tangent line at a=1, even though it
works if I use it by itself:
f(x)=x^2
def sl(a):
if a!=1:
m=(f(a)-f(1))/(a-1)
else:
m=f.diff(x)(1)
return m
sl(1)
2
L(a,x)=f(a)+sl(a)*(x-a)
L(1,x)
ValueError: power::eval(): division by zero
Thank you for any help.
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