I have use the @parallel and @fork decorators (as documented at
http://doc.sagemath.org/html/en/reference/parallel/sage/parallel/decorate.html)
also using the timeout parameter. Has anyone successfully managed to do
the following:
Suppose you have two functions f() and g() which take the same input and
produce the same output, using different methods. Sometimes one is faster,
sometimes the other, and I have no idea which inputs f() works faster than
g() or vice versa. So what I would like to do is set them both going in
parallel, and whenever one finished kill the other. I think I know how to
do everything except the "kill the other" part. Can anyone help?
As a test case (not the real one!) think of
def f(N):
return N.factor(algorithm='pari')
deg g(N):
return N.factor(algorithm='ecm')
sage: @parallel
....: def apply(func):
....: return func(29038109543453453498320938204932840238210981)
....:
sage: for res in apply([f,g]): print res; break
(((<function f at 0x7fb0537d6050>,), {}), 3^2 * 12248508919 *
263416276811813669131602539468011)
sage: f
<function f at 0x7fb0537d6050>
sage: g
<function g at 0x7fb0522551b8>
The first bit of the output shows that it is f which returns the result.
But I don't know if g stops working because of the 'break' -- does it?
John Cremona
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