Thank you very much for the answer. It works perfectly. 在 2019年4月28日星期日 UTC+2下午7:18:39，Peter Mueller写道： > > You can use an exception, something as follows: > > def is_lp_solvable(P): > try: > P.solve() > return True > except: > return False > > Am Sonntag, 28. April 2019 14:31:31 UTC+2 schrieb [email protected]: >> >> Hello everyone! I would like to ask a question about the solvability of a >> linear programming problem. >> I use sagemath to check whether my LP problem has any feasible solution >> or not. >> The program is similar to the following one without details >> sage: p = MixedIntegerLinearProgram(maximization=False, solver = "PPL") >> sage: w = p.new_variable(integer=True, nonnegative=True) >> sage: p.set_objective(w[0]) >> >> Then I use p.solve() to solve this problem, and when there is no feasible >> solution, the program will >> print out quite a few sentences with the last one like this: >> MIPSolverException: PPL : There is no feasible solution >> >> My question is whether I can define a True/False function such that when >> the LP porble p has any feasible solution, >> then it returens True; otherwise it returns False? >> >> Thank you very much for your kind help! >> >
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