What Sage are you using ?
Le vendredi 5 février 2021 à 21:41:09 UTC+1, [email protected] a écrit :
> I just realized that when faced with
>
> log(a)-log(b)
>
> Sage does not normally simplify that log(a/b), or vice-versa. I tried
> using f.simplify_full() and friends with no effect.
>
> Then I tried to enter
>
> ?simplify_full
>
> and got
>
> Object `simplify_full` not found.
>
> I notice that there is a simplify_log(), but that one does not do what I
> want either.
>
???
```
sage: var("a,b")
(a, b)
sage: (log(a)-log(b)).log_simplify()
log(a/b)
sage: (log(a)-log(b)).simplify_log()
log(a/b)
```
but, indeed :
```
sage: (log(a)-log(b)).simplify()
log(a) - log(b)
sage: (log(a)-log(b)).simplify_full()
log(a) - log(b)
```
> 1) Is there a way to do it?
>
See above
> 2) How can I find out what the various "simplify"s do?
>
The SR objects' methods are probably better documented than wrapper
functions.
> Thanks,
>
> Fernando
>
>
> --
> =============================================================
> Fernando Q. Gouvea http://www.colby.edu/~fqgouvea
> Carter Professor of Mathematics
> Dept. of Mathematics and Statistics
> Colby College
> 5836 Mayflower Hill
> Waterville, ME 04901
>
> If all you have is a hammer, everything looks like a nail.
>
>
>
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