Hi,
I am trying to solve the following equation for x, 1+2*log(x+1, 4)==2*
log(x,2)
I entered in the input "(1+2*log(x+1,
4)==2*log(x,2)).solve(x,algorithm='sympy',
domain='all')"
and the Output was
"{๐ฅโฃ๐ฅโโโงโ๐ฅ2log(2)+๐(๐ฅ+1)1log(2)=0}โ{๐ฅโฃ๐ฅโโโง๐ฅ2log(2)=0}"
The answer I am looking for is "x = 1+3^(1/2)."
--
You received this message because you are subscribed to the Google Groups
"sage-support" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to sage-support+unsubscr...@googlegroups.com.
To view this discussion on the web visit
https://groups.google.com/d/msgid/sage-support/4f7fb72f-b292-4abd-8740-9a5f50491a2an%40googlegroups.com.
