Thanks! That makes sense. I will try!

On Thursday, January 22, 2026 at 7:45:08 PM UTC+1 Nils Bruin wrote:

> You can get Z^m with the bilinear form on it simply by computing the Gram 
> matrix G of the pairing relative to v1,...,vm.
>
> If your pairing is non-degenerate, the lattice you're looking for is 
> Z^m/ker(G). and the bilinear form can be induced on that quotient from the 
> information that you have in G already.
> (you may well have to clear denominators from G in order to get sage to 
> compute ker(G) for you)
>
> If your pairing is degenerate then getting the Z^n -lattice that v1,...,vm 
> span needs to use the actual embedding in V. In that case, you can just 
> scale out the denominators of the coordinates of your v1,...,vm and compute 
> a Hermite normal form of the resulting integer matrix. That's a scaling 
> away from the actual lattice generated by v1,...,vm. Getting the Gram 
> matrix on that representation is also straightforward.
>
> These are not quite one-liners, but they do use fairly high-level linear 
> algebra, so it shouldn't be too onerous to do.
>
> Once you have the Gram matrix you can construct an "IntegralLattice" from 
> that.
>
> On Thursday, 22 January 2026 at 02:32:27 UTC-8 [email protected] 
> wrote:
>
>> If somebody could help me with the following problem I would appreciate 
>> it!
>>
>> Let V=QQ^n be an n-dimensional vector space over the rationals, equipped 
>> with a symmetric bilinear form B (given by its evaluation on the standard 
>> basis vectors of QQ^n).
>>
>> Assume given v1,..,vm in V. I would like to construct the IntegralLattice 
>> spanned
>> by the (vi)_i, equipped with the restriction of the bilinear form B. If 
>> it helps: v1, ..., vm generate V.
>>
>> Any ideas on how to do this in a nice way?
>>
>>
>>

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