#14352: Bug in parsing Maxima output with factorial
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Reporter: eviatarbach | Owner: burcin
Type: defect | Status: new
Priority: critical | Milestone: sage-5.9
Component: symbolics | Resolution:
Keywords: | Work issues:
Report Upstream: N/A | Reviewers:
Authors: | Merged in:
Dependencies: | Stopgaps:
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Description changed by eviatarbach:
Old description:
> Sage interprets the Maxima factorial operator as the inequality symbol in
> some cases:
>
> {{{
> sage: factorial(x) == 6
> factorial(x) == 6
> sage: _.simplify()
> x != 6
> }}}
>
> I set the priority to critical because this can produce wrong answers.
New description:
Sage interprets the Maxima factorial operator as the inequality symbol in
some cases:
{{{
sage: factorial(x) == 6
factorial(x) == 6
sage: _.simplify()
x != 6
}}}
I set the priority to critical because this can produce wrong answers. For
example,
{{{
bool((factorial(x) == 6).simplify().subs(x=2))
}}}
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Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/14352#comment:1>
Sage <http://www.sagemath.org>
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