#15060: The empty graph once again
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       Reporter:  darij                          |        Owner:
           Type:  defect                         |       Status:  new
       Priority:  major                          |    Milestone:  sage-5.12
      Component:  combinatorics                  |   Resolution:
       Keywords:  graphs, border cases, bitset,  |    Merged in:
  memleak                                        |    Reviewers:
        Authors:                                 |  Work issues:
Report Upstream:  N/A                            |       Commit:
         Branch:                                 |     Stopgaps:
   Dependencies:                                 |
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Comment (by darij):

 Replying to [comment:4 ncohen]:
 > What is wrong with "a graph is connected if any two vertices are linked
 by a path" ? An empty graph can be partitionned in connected component,
 i.e. only one : itself.

 Then the factorization of a graph into disjoint connected components is
 not unique. You can add as many empty components as you wish then.

 > I would love it to be {{{"ValueError: We don't know whether an empty
 graph is connected. We discussed it, and just never agreed on anything"}}}

 Sounds good :)

--
Ticket URL: <http://trac.sagemath.org/ticket/15060#comment:5>
Sage <http://www.sagemath.org>
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