#13186: Equality of Factorizations
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       Reporter:  caruso                  |        Owner:  tbd
           Type:  defect                  |       Status:  new
       Priority:  minor                   |    Milestone:  sage-5.12
      Component:  factorization           |   Resolution:
       Keywords:  equality factorization  |    Merged in:
        Authors:                          |    Reviewers:
Report Upstream:  N/A                     |  Work issues:
         Branch:                          |       Commit:
   Dependencies:                          |     Stopgaps:
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Comment (by chapoton):

 Well, one must choose the meaning of equality.

 One precise meaning would be
  - a factorisation is made of a unit and a set/list of factors
  - two factorisations are equal if they have the same unit and the same
 factors (up to order maybe)

 Another possible solution would be to consider the unit as just any other
 factor. I do no like this solution, and I prefer the previous (current)
 behavior

 If you want, you can maybe ask for opinions on sage-devel.

 Something else: I have just thought that it would sometimes be good to
 separate factors in the center of the ring (commuting) and other factors,
 and to implement "partially commutative factorisations". But this is
 something for the wishlist.

--
Ticket URL: <http://trac.sagemath.org/ticket/13186#comment:8>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica, 
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