#8373: finite fields constructed with non-primitive defining polynomial
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       Reporter:  rkirov        |        Owner:  cpernet
           Type:  enhancement   |       Status:  new
       Priority:  minor         |    Milestone:  sage-6.3
      Component:  finite rings  |   Resolution:
       Keywords:                |    Merged in:
        Authors:                |    Reviewers:
Report Upstream:  N/A           |  Work issues:
         Branch:                |       Commit:
   Dependencies:                |     Stopgaps:
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Description changed by jdemeyer:

Old description:

> Consider the following code:
> {{{
> sage: R.<x> = PolynomialRing(GF(2))
> sage: K.<a> = GF(16, modulus=x^4+x^3+x^2+x+1)
> sage: a^5
> 1
> }}}
>
> This is all fine mathematically, as long as the user is clear what a is
> and isn't (it isn't a generator for the multiplicative group of the
> finite field). So the options as I see them (in increasing difficulty for
> implementation):
>
> 1)GF already checks modulus for irreducibility, just add check for
> modulus.is_primitive().
>
> 2)Rewrite the help for the GF function to indicate that the function does
> not return a generator necessarily (like in this specific case).
>
> 3)Find an actual generator (that might not be the polynomial x) and
> return that.
>

> Opinions?

New description:

 Add an argument `modulus="primitive"` to the finite field generator `GF()`
 such that the chosen generator is guaranteed to be a generator of the
 multiplicative group.

--

--
Ticket URL: <http://trac.sagemath.org/ticket/8373#comment:5>
Sage <http://www.sagemath.org>
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