#13055: Better default precision for .n() method
-------------------------------------+-------------------------------------
       Reporter:  dsm                |        Owner:  burcin
           Type:  enhancement        |       Status:  needs_review
       Priority:  major              |    Milestone:  sage-
      Component:  symbolics          |  duplicate/invalid/wontfix
       Keywords:  numerical_approx,  |   Resolution:
  sd40.5                             |    Merged in:
        Authors:                     |    Reviewers:
Report Upstream:  N/A                |  Work issues:
         Branch:                     |       Commit:
   Dependencies:                     |     Stopgaps:
-------------------------------------+-------------------------------------

Comment (by jdemeyer):

 Losing precision is a ''feature'' of the `.n()` method, that's what it
 does. The `x.n()` method asks for a ''numerical approximation'' of `x` to
 a precision of 53 bits. This is easily explained. I also like the fact
 that neither the implementation nor the user should need to worry about
 what `x` is, the output is a real/complex number with 53 bits of
 precision.

 If you think that `.n()` is wrong, what should `(2/3).n()` return then?
 The only possible answer which doesn't lose precision is the rational 2/3.

--
Ticket URL: <http://trac.sagemath.org/ticket/13055#comment:12>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica, 
and MATLAB

-- 
You received this message because you are subscribed to the Google Groups 
"sage-trac" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/sage-trac.
For more options, visit https://groups.google.com/d/optout.

Reply via email to