#7560: len(t_span) > 2 case creates len(t_span) - 1 solutions
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Reporter: adavid | Owner: jkantor
Type: defect | Status: new
Priority: minor | Milestone: sage-4.3
Component: numerical | Keywords: t_span
Work_issues: | Author:
Upstream: N/A | Reviewer:
Merged: |
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From: Ryan
{{{
Hello all,
I've just started using Sage, and I'm currently trying to use the
ode_solver class to solve some simple differential equations. I was
having some problems setting up my own program based on this class
until I realized that the number of points in the solution does not
match the number of points requested by the t_span variable. For
example, when I run this script:
_________
#!/usr/bin/env sage-python
from sage.all import ode_solver
def f(t, y):
return [y[1], -y[0]]
T = ode_solver()
T.function=f
T.y_0=[1, 1]
T.ode_solve(t_span=[0, 10], num_points=100)
print len(T.solution)
T.ode_solve(t_span=[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10])
print len(T.solution)
_________
I get returned values of 101 and 10, where I would expect 100 and 11.
I don't know about the first case, but for the second case, the
solution for the last value (10) is missing. I was able to circumvent
this problem by appending a dummy variable to the end of t_span, but
I'm wondering if this is the expected behavior. Is there something
about the solution that I'm missing? I am currently using Sage 4.2.1
that I built from source in a Gentoo Linux distro.
}}}
--
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/7560>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica,
and MATLAB
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