#8574: Length of a finite word defined by an iterator is broken
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Reporter: slabbe | Owner: slabbe
Type: defect | Status: new
Priority: major | Milestone: sage-5.0
Component: combinatorics | Keywords:
Author: | Upstream: N/A
Reviewer: | Merged:
Work_issues: |
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{{{
---------- Forwarded message ----------
From: Timo Jolivet
Date: 2010/3/20
Subject: bug WordMorphism ?
Un bug bizarre :
sage: s = WordMorphism('0->0,1->%s'%('1'*100))
sage: s(
KeyboardInterrupt
sage: s = WordMorphism('0->000,1->%s'%('1'*100))
sage: s('0')
word: 000
sage: s('1')
word: 1111111111111111111111111111111111111111...
sage: len(s('0'))
3
sage: len(s('1'))
---------------------------------------------------------------------------
TypeError Traceback (most recent call
last)
/slabbe_hacked_macbook/<ipython console> in <module>()
TypeError: an integer is required
C'est d'autant plus bizarre que le code suivant marche :
sage: len(Word('1'*100))
100
}}}
--
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/8574>
Sage <http://www.sagemath.org>
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