#8674: Comparison of combinatorial class of words with word paths is broken
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   Reporter:  slabbe         |       Owner:  slabbe    
       Type:  defect         |      Status:  needs_info
   Priority:  major          |   Milestone:  sage-4.4  
  Component:  combinatorics  |    Keywords:            
     Author:                 |    Upstream:  N/A       
   Reviewer:                 |      Merged:            
Work_issues:                 |  
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Changes (by abmasse):

  * status:  needs_review => needs_info


Comment:

 I understand that you want to correct the function `is_endormorphism`, but
 there is something strange about combinatorial class comparison.

 For instance, I get the following:

 {{{
 sage: Words('ab') == WordPaths('ab')
 False
 sage: Words('ab') <= WordPaths('ab')
 True
 sage: Words('ab') >= WordPaths('ab')
 False
 }}}

 Wouldn't we want

 {{{
 sage: Words('ab') == WordPaths('ab')
 True
 }}}

 or is there something I miss ?

 If it is a problem, maybe it's not necessary to fix the `__eq__` operator
 now but do it in another ticket, but since you're at it...

-- 
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/8674#comment:3>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica, 
and MATLAB

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